Family tree Tanke - Heimann » Maria Hennaert (1631-????)

Personal data Maria Hennaert 


Household of Maria Hennaert

She is married to Ludovicus Stepers.

They got married on July 4, 1655 at Oostvleteren, 8640, België, she was 23 years old.

Do you have supplementary information, corrections or questions with regards to Maria Hennaert?
The author of this publication would love to hear from you!


Timeline Maria Hennaert

  This functionality is only available in Javascript supporting browsers.
Click on the names for more info. Symbols used: grootouders grandparents   ouders parents   broers-zussen brothers/sisters   kinderen children

Ancestors (and descendant) of Maria Hennaert

Petrus Hennaert
± 1600-????
Joanna DeRaet
± 1605-????

Maria Hennaert
1631-????

1655

Ludovicus Stepers
± 1628-????


With Quick Search you can search by name, first name followed by a last name. You type in a few letters (at least 3) and a list of personal names within this publication will immediately appear. The more characters you enter the more specific the results. Click on a person's name to go to that person's page.

  • You can enter text in lowercase or uppercase.
  • If you are not sure about the first name or exact spelling, you can use an asterisk (*). Example: "*ornelis de b*r" finds both "cornelis de boer" and "kornelis de buur".
  • It is not possible to enter charachters outside the standard alphabet (so no diacritic characters like ö and é).



Visualize another relationship

The data shown has no sources.


About the surname Hennaert

  • View the information that Genealogie Online has about the surname Hennaert.
  • Check the information Open Archives has about Hennaert.
  • Check the Wie (onder)zoekt wie? register to see who is (re)searching Hennaert.

When copying data from this family tree, please include a reference to the origin:
Harry Tanke, "Family tree Tanke - Heimann", database, Genealogy Online (https://www.genealogieonline.nl/stamboom-tanke-arends/I47785.php : accessed May 14, 2024), "Maria Hennaert (1631-????)".